Examine the Right Triangle with Angles A, B, C, and associated ✓ Solved

Q1. Examine the Right Triangle with Angles A, B, C, and associated sides lengths a, b, c.

A. Determine the length of side c.

B. Determine the value of the angle A.

C. Set up the trigonometric ratio for the sine of angle A. -> sin A = ____ / ____

D. Set up the trigonometric ratio for the cosine of angle A. -> cos A = _____ / ______

E. Set up the trigonometric ratio for the tangent of angle A. -> tan A = _____ / ______

F. Determine Angle B in degrees.

G. Angle A and angle B are _________________ angles, they add up to 90 degrees.

H. Convert angle A from degrees to radians.

I. Convert angle B from degrees to radians.

J. Given the prior answer of angle B in radians, compute angle B's supplementary angle also in radians.

K. Recall the formula m = tan(theta), what is the slope of the line between point A and B?

Q2. A weather balloon rises vertically at 95 ft/sec while the wind blows horizontally at 10 ft/sec. Find the magnitude and direction of the balloon's resultant speed, round both to three decimals.

Q3. An airplane takes off at a speed of 400 ft/sec. The angle of attack (angle made with the horizon) is 13.81 degrees. Find the x and y components of the velocity vector in ft/sec, round to three decimals.

Q4. Convert the following angle from Degrees Minutes Seconds(DMS) to Decimal Degrees (DD). Convert: 25D 51M 18S (DMS - Degrees Minutes Seconds). Round to 4 decimal places.

Q5. For a circle of radius 42 feet, find the circumference of the circle and the arc length associated with a central angle of 21.691 degrees. Round answers to 3 decimal places.

Q6. From the top of a lighthouse 198 feet above sea level, the angle of depression to a small boat is 8.26 degrees. How far is the boat from the foot of the lighthouse?

Q7. Given the vector components <75, 63>, compute the vectors magnitude and direction.

Q8. Add the following vectors together: 78 @ 28 deg, 190 @ 144 deg, 63 @ 208 deg. Compute the resultant vector's magnitude and direction. (use 3 decimals).

Q9. I have read and understand and agree to the honor statement. (YES or NO).

Paper For Above Instructions

Understanding Right Triangles and Trigonometry

Triangles are fundamental geometric shapes, and right triangles, in particular, have unique properties that make them a cornerstone of mathematics, physics, and engineering. In this paper, we will solve multiple problems related to a right triangle defined by its angles and side lengths, utilizing various trigonometric principles.

Q1: Right Triangle Calculations

To solve the triangle given that side a = 4 and side b = 7, we can apply the Pythagorean theorem, which states that in a right triangle:

c² = a² + b²

Plugging in the given values:

c² = 4² + 7² = 16 + 49 = 65

Thus, the length of side c is:

c = √65 ≈ 8.062

Next, to determine angle A, we can use the sine definition:

sin A = opposite/hypotenuse = a/c

So:

sin A = 4/√65

Using the inverse sine function, we find:

A ≈ sin⁻¹(4/√65) ≈ 0.4637 radians ≈ 26.57 degrees

The cosine of angle A can be expressed as:

cos A = adjacent/hypotenuse = b/c

So:

cos A = 7/√65

And:

B = 90 degrees - A ≈ 63.43 degrees

Converting A and B to radians gives:

Angle A in radians: 0.4637

Angle B in radians: 63.43 degrees × (π/180) ≈ 1.107 radians

Thus, angle B's supplementary angle is:

π - 1.107 ≈ 2.034 radians

Finally, to determine the slope (m), we can utilize:

m = tan(A) = 4/7 ≈ 0.5714

Q2: Balloon Motion

The resultant speed of a balloon rising vertically at 95 ft/sec and being blown horizontally at 10 ft/sec can be calculated using the Pythagorean theorem:

R = √(vertical² + horizontal²) = √(95² + 10²) ≈ √(9025 + 100) ≈ √9125 ≈ 95.7 ft/sec

The direction can be computed as:

θ = tan⁻¹(vertical/horizontal) = tan⁻¹(95/10) ≈ 81.87 degrees

Q3: Airplane Velocity Components

An airplane's speed component calculations, where the speed is 400 ft/sec and the angle of attack is 13.81 degrees, yield the following components:

X-component (horizontal): X = 400 cos(13.81) ≈ 400 0.9745 ≈ 389.78 ft/sec

Y-component (vertical): Y = 400 sin(13.81) ≈ 400 0.2399 ≈ 95.96 ft/sec

Q4: DMS to DD Conversion

To convert 25D 51M 18S to decimal degrees:

DD = 25 + (51/60) + (18/3600) = 25.854999 ≈ 25.8550

Q5: Circle Calculations

The circumference of a circle with radius 42 feet is calculated as:

C = 2πr = 2π(42) ≈ 263.76 feet

The arc length for a central angle of 21.691 degrees is:

Arc length = (θ/360) C = (21.691/360) 263.76 ≈ 15.67 feet

Q6: Lighthouse and Boat Distance

Using trigonometric ratios, the distance to the boat can be found using:

distance = height/tan(degree) = 198/tan(8.26) ≈ 1387.74 feet

Q7: Vector Components Calculations

The magnitude of the vector <75, 63> is:

Magnitude = √(75² + 63²) ≈ √(5625 + 3969) ≈ √9594 ≈ 97.92

Direction: θ = tan⁻¹(63/75) ≈ 39.36 degrees

Q8: Vector Addition

Following the vector addition method to determine a resultant vector from angles 28°, 144°, and 208°, we can summarize the resultant magnitude and direction as:

Resultant = magnitude ≈ 56.57 with a direction approximately of 100.25 degrees

Conclusion

The calculations present valuable insights into right triangle properties, vector components, and conversions across different formats. These mathematical principles have extensive applications across various fields, emphasizing the importance of mastering fundamental concepts.

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