Pls only answer if you are going to answer all of them thanks i got alot in my h
ID: 1002856 • Letter: P
Question
Pls only answer if you are going to answer all of them thanks i got alot in my hands cuz of finals, and don't have time to do them, Appreciate it, trust that they'll be right
1) The electrochemical cell described by the balanced chemical equation has a standard emf of 0.35 V. Calculate the value (J) for the Wmax that the cell can do under standard conditions. Round your answer to 3 significant figures.
2MnO42-(aq) + 2Hg2+(aq) ? 2MnO4-(aq) + Hg22+(aq)
2) The voltaic cell described by the balanced chemical reaction has a standard emf of 4.05 V. Calculate the equilibrium constant (Kc) for the reaction at 25 oC. Round your answer to 3 significant figures.
F2(g) + Mn(s) ? 2F-(aq) + Mn2+(aq)
St. Red. Pot. (V)
Constants
Faraday's Constant
3) The voltaic cell described by the cell notation has an Eo of 0.68 V. Calculate the Wmax (kJ) the cell has done if 6.4700 mol of MnO4-(aq) (Molar Mass - 118.94 g/mol) reacts. Round your answer to 3 significant figures.
Pt(s) l VO2+(aq), VO2+(aq), H+(aq) ll H+(aq), MnO4-(aq) l MnO2(s) l Pt(s)
F = 96485 C
5) The electrochemical cell described by the balanced chemical equation has a standard cell potential of -0.37 V. Calculate the value (kJ) for the standard free energy change of the cell. Round your answer to 3 significant figures.
1) The electrochemical cell described by the balanced chemical equation has a standard emf of 0.35 V. Calculate the value (J) for the Wmax that the cell can do under standard conditions. Round your answer to 3 significant figures.
2MnO42-(aq) + 2Hg2+(aq) ? 2MnO4-(aq) + Hg22+(aq)
Explanation / Answer
2MnO42-(aq) + 2Hg2+(aq) 2MnO4-(aq) + Hg22+(aq)
w(max) = -nFEo
n = number of moles of e- which is transferred in the reaction; 2
F = 1 Faraday = 96,485 Coulombs (C)
Eo =0.56- 0.91
= -0.35 V = -0.35 J/C
w(max) = -nFEo = -2 x 96,485 C x (-0.35 J/C)
= 67539.5 J