CHM 111 Pre-Lab Preparation of Aspirin The balanced reaction for the preparation

Question

CHM 111 Pre-Lab Preparation of Aspirin The balanced reaction for the preparation of aspirin (acetylsalieylic acid) is CH,COOFH Salicylic Acid Acetic Anhydride Aspirin Acetic Acid 1 I. Calculate the molecular weights for cach reactant and product in the reaction a Salicylic Acid gmole b. Acetic Anhydride g/mole LI4 mole c. Aspirin g/mole d. Acetic Acid g/mole 2. From the reaction above: a. When 1 mole of Salicylic Acid is used in the reaction _mole(s) of Acetic Anhydride will be used. When 0.250 moles of Salicylic Acid is combined with 0.250 moles of Acetic Anhydride, b. ydride,mole(s) of Aspirin will be produced. c. When 0.0175 moles of Salicylic Acid is combined with 0.0675 moles of Acetic mole(s) of Aspirin will be produced. g reactant, and_ Anhydride, will will be the limiting reactant, and be the excess reactant. grams of Aspirin d. The number of moles of Aspirin in c above equals (actual or theoretical) yield. The amount of Aspirin in d represents the

Explanation / Answer

The chemical equation for the synthesis of aspirin is

C7H6O3 + C4H6O3 –> C9H8O4 +C2H4O2

Reaction takes place in the presence of phosphoric acid.

        2.

              a) When 1 mole of salicylic acid is used in reaction 1mole of acetic anhydride will be used.

b) When 0.250 moles of Salicylic acid is combined with 0.250 moles of Acetic anhydride 0.250        moles of Aspirin will be produced.( For every mole of aspirin produced, 1 mole of salicylic acid was needed.)

c)When 0.0175 moles of Salicylic acid is combined with 0.0675 moles of Acetic anhydride 0.0175  moles of Aspirin will be produced. Salicylic acid will be limiting reactant; Acetic anhydride will be excess reactant.

d) 0.0175 of moles of Aspirin = 0.0175 moles x 180.16g/mole = 3.15g

e) The amount of Aspirin in d represent the theoretical yield.

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