There are two lead iodides. Predict the oxidation states of each element in the
ID: 1008924 • Letter: T
Question
There are two lead iodides. Predict the oxidation states of each element in the compound formed by these elements, and write the formula for the compound. Write the ground state electron configuration of each oxidation state that you used, showing unpaired electrons and identifying the valence electrons. There are two lead iodides. Predict the oxidation states of each element in the compound formed by these elements, and write the formula for the compound. Write the ground state electron configuration of each oxidation state that you used, showing unpaired electrons and identifying the valence electrons.Explanation / Answer
1) PbI2
oxidation state of Pb = +2
Pb : [Xe] 4f14 5d10 6s2 6p2
Pb+2 : [Xe] 4f14 5d10 6s2 6p0
Valence electrons = 2 (6s2)
2) PbI4 ( unstable compound due to inert pair effect)
oxidation state of Pb = +4
Pb : [Xe] 4f14 5d10 6s2 6p2
Pb+4 : [Xe] 4f14 5d10 6s0 6p0
Valence electrons = 0 in 6 shell. so next valence will be 5 (5s2 5p6 5d10) so 18e- in 5 shell