Part A What is the ground-state electron configuration of a neutral atom of iron
ID: 1013187 • Letter: P
Question
Part A
What is the ground-state electron configuration of a neutral atom of iron?
Express your answer in condensed form, in order of increasing orbital energy. For example, [He]2s22p2 would be entered as [He]2s^22p^2 .
Part B
What is the ground-state electron configuration of the oxide ion O2?
Express your answer in condensed form, in order of increasing orbital energy. For example, [He]2s22p2 should be entered as [He]2s^22p^2 .
Part C
Which element has the following configuration: [Xe]6s24f4?
Enter the chemical symbol for the element.
Explanation / Answer
A) iron (Fe) = 26 atomic number
Fe = [Ar]4s^23d^6
B) O = 8 atomic number so 10 electrons
O-2 = 10 electrons = 1s^22s^22p^6 = [He]2s^22p^6 = [Ne]
C) [Xe]6s^24f^4
Xe = 54
54 + 2+4 = 60
atomic number 60 = Nd = Neodymium
element = Nd