Possible answers: A) be suitable because Delta S univ > 0. B) not be suitable be

Question

Possible answers: A) be suitable because Delta S univ > 0. B) not be suitable because Delta S univ > 0. C) be suitable because Delta S univ < 0. D) not be suitable because Delta S univ < 0. Part B A particular solvent with Soap 112.9 J/(K-mol and Hvap-38.0 kJ/mol is being considered for an experiment. In the experiment, which is to be run at 75 C, the solvent must not boil. Based on the overall entropy change associated with the vaporization reaction, would this solvent be suitable and why or why not? O be suitable because Suiv > 0. O not be suitable because Suniv > 0. O be suitable because Suniv

Explanation / Answer

we know that

dSsurr = -dH/T

given

tempature (T) = 75 C = 75 + 273 K = 348 kelvin

dH = 38 x 1000 J /mol

so

dSsurr = - 38 x 1000 / 348

dSsurr = -109.1954 J/mol

now

we know that

dSuniv = dSsys + dSsurr

given

dSsys = 112.9

so

dSuniv = 112.9 - 109.1954

dSuniv = 3.7046 J/mol

so

dSuniv > 0

now

as the overall entropy change (dSuniv) is positive

we can say that the boilling or vaporization of the given solvent is spontaneous

so

boiling or vaporization of the solvent will occur

but

the requirement is that the solvent must not boil

so

the solvent would not be suitable becuause dSuniv > 0

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