Question
need help balancing the cathode and anode
A galvanic cell is powered by the following redox reaction: 210 (aa) 12 H (aq) 10 Br (eq) Ir(s) 6 H20() 5 Br 2 Answer the following questions about this cell. If you need any electrochemical data be sure you get it from the ALEKS Data ta write a balanced equation for the half reaction that takes place at the 0 write a balanced equation for the half reaction that takes place at the L Calculate the cel woltage under standard conditions Round your answer to 2 decimal
Explanation / Answer
Balanced cathode reaction,
2IO3-(aq) + 12H+(aq) + 10e- ---> I2(s) + 6H2O(l)
Balanced anode reaction,
2Br- ----> Br2(l) + 2e-
Cell voltage Eo = 1.195 - 1.066 = 0.13 V