In a study conducted at the same temperature, the following data for reaction pr
ID: 1019371 • Letter: I
Question
In a study conducted at the same temperature, the following data for reaction producing nitrosyl bromide were collected.Trial Initial NO M Initial Br2 M Initial Rate M/s 1. 0.150. 0.240. 39 2. 0.300. 0.240. 157 3. 0.300. 0.480. 314
What is the rate of the reaction when the initial concentration of NO is 0.400M and that of Br2 is 0.255M? In a study conducted at the same temperature, the following data for reaction producing nitrosyl bromide were collected.
Trial Initial NO M Initial Br2 M Initial Rate M/s 1. 0.150. 0.240. 39 2. 0.300. 0.240. 157 3. 0.300. 0.480. 314
What is the rate of the reaction when the initial concentration of NO is 0.400M and that of Br2 is 0.255M?
Trial Initial NO M Initial Br2 M Initial Rate M/s 1. 0.150. 0.240. 39 2. 0.300. 0.240. 157 3. 0.300. 0.480. 314
What is the rate of the reaction when the initial concentration of NO is 0.400M and that of Br2 is 0.255M?
Explanation / Answer
from experimental data it is clear that.
reaction is second order with respect to NO first order with respect to Br
so rate law as follows
rate = K [NO]2[Br2] calculate K from experimental data
K = rate / [NO]2[Br2]
K = 39 / (0.15)2(0.24)
K = 39 / 0.0054
K = 7222.2 M-2s-1now by using value of K calculate rate at given concentration
rate = 7222.2 [0.4]2[0.255]
rate = 294.7 M/s