Question
Increasing the temperature of an exothermic reaction results in more products and fewer reactants. More reactants and fewer products. More reactants and products fewer reactants and products. No change in the quantities of reactants and products. In a steam engine, steam in a cylinder is compressed by a piston exerting 13.5 atms of external pressure. The volume of the cylinder decreases by 20.1 L and simultaneously the steam heats up. If the total energy change of the steam is 32.8 kJ, calculate the heat flow into/out of the steam (101.3 J = 1 L atms) +239 J +5310 J +27.5 kJ -5310 J -27.5 kJ The equilibrium constants for the two reactions are known: M +4 L leftwards arrow over reversiblearrow [ML_4]^m-4 K_f HL leftwards arrow over reversiblearrow H + L K_s What is the equilibrium constant, K for the reaction, M + 4 HL leftwards arrow over reversiblearrow [ML_4]^m-4 + 4 H' ? K_p K_a K_f + 4K_a K_f + K_a^a K_tK_a^4 K_f K_a^1/4
Explanation / Answer
37) According to Le chatelier principle, a decrease in temperature favours product formation in case of exothermic reaction, as the reaction itself produce heat during the course of the reaction or the reaction moves in forward direction and on the other hand an increase in temperature favours backward reaction. Thus as asked in the question increasing the temperature of an exothermic reaction result in more reactant and less product.