TY 2) Write the name for So(S04)2. Remember that Sn forms several ions. 32) A) t

Question

TY 2) Write the name for So(S04)2. Remember that Sn forms several ions. 32) A) tin@) sulfate B) tin(IV) sultate C) tinT) sulfite D) tisl) sulfite E) tin sulfide 33) W rite the formula for copper(T) sulfate pentahydrate 33) A) Cu2503 H5 B) Cu2S Hbo C) Cus04 SH20 D) CuS 5H20 34) Give the name for H2S04 34) A) sulfurous acid B) sulfuric acid O persulfuric acid D) hy posulfurous acid persulfurous acid 35) Caleulate the molar mass of ACoph. 35) A) 86.03 g/imo B) 13999 gmol C) 204.13 gimol D) 56.00 g/lmol E 258.09 gmol 36) Determine the number of moles of sodium in 3.20 moles of sodium hydrogen phosphate 36) A) 3.20 moles of sodium B) 1.60 moles of sodium C) 960 moles of sodium D) 6.40 moles of sodium E 1280 moles of sodium 37) Calculate the mass percent composition of sulfur in Al 2(504b 37) A)21 38% B) 28.12% Q4273% Dj 3597% E) 9372% 38) How many atoms of carbon are contained in 47 6 g of Al2lCO3l3? The molar mass of Alz(CO3)hs 38) is 233.99 gimol A) 2.96 1024 Catoms 8) 368 1023 C atoms C) 110 1024 Catoms D) 1.23 1023 Catoms E) 287-1025 C atoms

Explanation / Answer

32) option b

33) option c

34) option b

35) option c

36) option d

37) Firstly we will calculate the molar mass of the compound. From there we can calculate the percent of each element by using the mass of each element:

Al - 2(26.98)/342.2 x 100 = 15.8%

S - 3(32.065)/342.2 x 100 = 28.1%

O - 12(16)/342.2 x 100 = 56.1%

So for Sulfur, the mass percent would be 28.1%.

Option b

38) No of moles of sample= 47.6 g / 233.99 g/mol = 0.2034275 mol

0.2034275 mol times 6.022 x 10^23 formula units / mol = 1.225 x 10^23 formula units

1.225 x 10^23 formula units times 9 oxygen atoms per formula unit = 1.1025 x 10^24 oxygen atoms

Option c

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