I need the answers for both pages c. Your duodenum is the region of your small i
ID: 1028136 • Letter: I
Question
I need the answers for both pages
c. Your duodenum is the region of your small intestine just past your stomach. It's the region where sodium bicarbonate secreted from your pancreas neutralizes your stomach acid, producing carbonic acid (which is then absorbed into your bloodstream and released as CO2 when you exhale-biology is incrediblel), Complete the following chemical reaction that occurs in your duodenum H+ + NaHCO3 d. Below is a K expression for a certain chemical reaction involved in the production of acid rain. Write a balanced chemical equation for the reaction from the K expression. (note one of the chemical species will actually be a gas. We'll give a bonus point if you can write the correct subscripts as well) Question 3-Acidity and Carbonates co2 dissolving in water drives most of the acidic weathering of minerals on our planet! This question will rely on the following chemical reactions and their K values: H2CO3(aq) HCO3-(aq) + H(aq) HCO3(aq) CO32-(aq) + H+ (aq) CaCO3 (s) Ca2+ (aq) + co,2. (aq) + K = 1053 = 10.10.3 Ksp-10-8.4 a. What is the pH at which you would predict [H,COl [HCOs1 at sExplanation / Answer
H+ + NaHCO3 === Na++ CO2 + H2O
d. The indexes are equal to the stoichiometric coefficients so the reaction will be:
K = products / reactants so we know that NO2 is the reactant
the other compounds are products so
2NO2 (g) + H2O (l) == 2H+ + NO2- + NO3- , this is the equation according to the equilibrium constant from the statement, NO2 is a gas, acid rain involves water that is why we have to put it, it does not appear on the equilibrium constant relation because it is a liquid.
As a reference : the acid rain reaction is commonly described as
2NO2 (g) + H2O (l) == HNO2 + HNO3-
3. acids
according to hendersson hesselbach equation the ph of a weak acid is
Ph = Pka + log (acid / conjugated base), if conjugated base equals the acid , in terms of concentration then
PH = PKa
so when (H2CO3) = (HCO3)
10-6.3 = 5.011x10-7
PH = -log (5.011x10-7) = 6.3
*please post the rest of the questions on a different post =)