If you could please explain how to receive the answers in blue it would be great
ID: 1029891 • Letter: I
Question
If you could please explain how to receive the answers in blue it would be greatly appreciated.
na Equation Question 8 0/10 points What are the products of this equation when related to Ka? Write subscripts and superscripts as regular text and do not use spaces. Place H30+ and OH as the second item. In the case of bases, attach the H to the atom at the end of the compound accepting it. Charges need to be placed at the end of compounds CH3OH + H2O--> For example, the answer for CH3COOH+ H20 is CH3COO-+H30+ For example, the answer for CH3COO- + H20is CH3COOH+OH Answer: X (CH30-+H30+) Kb Equation Question 9 0/ 10 points What are the products of this equation when related to Kb? Write subscripts and superscripts as regular text and do not use spaces. Place H30+ and OH- as the second item. In the case of bases, attach the H to the atom at the end of the compound accepting it. Charges need to be placed at the end of compounds. CH3SH + H20 > For example, the answer for CH3COOH H20-is CH3COO-+H30+ For example, the answer for CH3COO- + H20->is CH3COOH+OH Answer: X (CH3SH2++OH-Explanation / Answer
(8) Ka means acid dissociation constant.Soo CH3OH acts as an acid there by it looses a proton.
The balanced chemical reaction is
CH3OH+ H2O ----> CH3O- + H3O+
(9) kb means base dissociation constant.That means it accepts a proton .
The balanced chemical reaction is
CH3SH + H2O ----> CH3SH+ + OH-
(10) HF + CH3Li ----> CH4 + LiF