Cal State LA-CHEM 220 × C | ? www.saplinglearning.com/ibiscms/modibis/view.php?i
ID: 1034526 • Letter: C
Question
Cal State LA-CHEM 220 × C | ? www.saplinglearning.com/ibiscms/modibis/view.php?id=5143299 w. : Apps·Home Cal State LA Home Chegg.com 9 Program Biology, B D Los Angeles County ? All Opportunities-C d. Cal State LA CHEM Application for a 201 2018 Blanca Fla aga Sapling Learning Jump to.. Salvador Prieto- macmilan learning - Print CalalatorPeriodic Table Question 8 of 24 Available From: Due Date: Points Possible: Grade Category: 3/17/2018 09:00 AM 4/1/2018 11:59 PM 100 Graded Organic Chemistry Roberts & Company Publishers presented by Saping Leaming Complete the equations for the following equilibria and calculate Keq Species nk. ?? 1100 pKSpecies pka NH 35 HO 5.74 NH4 9.25H*-1.74 proper scientific notation Policies: B-HW You can check your answers You can view solutions when you complete or give up on any question. You have five attempts per question. There is no penalty for incorrect answers. (a) ammonia (acting as a base) reacts with water (acting as an acid) Number (b) ammonia (acting as an acid) reacts with water (acting as a base) eTextbook Number 10 1 Help With This Topic Which of these reactions is more important (i.e. prevalent) in an aqueous solution of ammonia? 12 1 13 1 14 2 15 1 16 O Web Help &Videos; O reaction (a) O reaction (b) O Technical Support and Bug Reports Previous Give Up 8 View Salution Check Answer NextExit Hint O Type here to search 201 PM 3/28/2018Explanation / Answer
a)
NH3 + H2O <-------------> NH4+ + OH-
Keq = [NH4+] [OH-] / [NH3]
= (1 / Ka(NH4+) ] x KaH2O
= (1/ 10^-9.25 ) x 10^15.74
Keq = 3.24 x 10^-7
b)
NH3 + H2O <-----------> NH2- + H3O+
Keq = 10^-35 / 10^1.74
Keq = 1.82 x 10^-37
reaction a) is more important