Should a precipitation of Pb(IO 3 ) 2 (s) form when 55.0 ml of 0.0450 M Pb(NO 3
ID: 1036314 • Letter: S
Question
Should a precipitation of Pb(IO3)2(s) form when 55.0 ml of 0.0450 M Pb(NO3)2 (aq) solution is added to 48.0 ml of 0.215 M NaIO3(aq) solution? Assume that at the temperature at which the experiment is performed, Ksp of Pb(IO3)2(s) is 2.8 x 10-13 . All work must be shown- a guess is not sufficient!
Should a precipitation of Pb(IO3)2(s) form when 55.0 ml of 0.0450 M Pb(NO3)2 (aq) solution is added to 48.0 ml of 0.215 M NaIOs(aq) solution? Assume that at the temperature at which the experiment is performed, Ksp of Pb(IOs)2(s) is 2.8 x 10 All work must be shown- a guess is not sufficient! aud which the experiment isExplanation / Answer
Pb+2 concentration = millimoles / total volume
= 55 x 0.0450 / (55 + 48)
= 0.0240 M
IO3- concentration = millimoles / total volume
= 48 x 0.215 / (55 + 48)
= 0.100 M
Q = [Pb+2] [IO3-]^2
Q = (0.0240) (0.100)^2
Q = 2.41 x 10^-4
Q > Ksp . so the precipitate will form