Problem 18.30 Your answer is partially correct. Try again. Germanium to which 10
ID: 1036553 • Letter: P
Question
Problem 18.30 Your answer is partially correct. Try again. Germanium to which 1024 m3 Ga atoms have been added is an extrinsic semiconductor at room temperature, and virtually all the Ga atoms may be thought of as being ionized (i.e., one charge carrier exists for each Ga atom) (a) Is this material n-type or p-type? p-type (b) Calculate the electrical conductivity of this material, assuming electron and hole mobilities of 0.26 and 0.028 m2/v-s, respectively G-T160200 the tolerance is +/-2% Click if you would like to Show Work for this question: (?-m)-1 Open Show Work SHOW HINT SHOW SOLUTIONExplanation / Answer
ANSWER:
(a) The semiconductor is p-type as the impurity belongs to group 13. There will be one electron deficiency because group 13 element (Ga) have 3 valence electron and Ge has four valence electrons. This results in hole formation.
(b) For extrinsic semiconductors electrons carriers (e) << hole carriers (p)
hence Conductivity for p-type semiconductor = p X e X Mp
e = charge on electron = 1.6 X 10-19C, p = number of holes/m3 ; Mp = hole mobility,
Conductivity = 1.6 X 10-19C X 1024 / m3 X 0.028 m2/V-s = 4.48 X 103 (Ohm meter)-1