I know that it goes like this: Cu(NO3)2 + Ba(OH)2 --> Cu(OH)2 + Ba(NO3)2. Howeve

Question

I know that it goes like this: Cu(NO3)2 + Ba(OH)2 --> Cu(OH)2 + Ba(NO3)2. However, please explain the spectator ions and make sure I have the correct answer. Also, if possible, can you provide brief step-by-step explanations, too? Thank you very much. (Could it be that no precipitate is formed? As far as I know, spectator ions are ions that appear in both sides of the equation. Since they both exist on both sides, does that mean they're not spectator ions?)

Which of the following statements is true when a solution of Cu(NO3)2(aq) is mixed with a solution of Ba(OH)2(aq)? BaNO3 will precipitate and Cu2+ and OH- are spectator ions CaO will precipitate and Ba2t and NO3 are spectator ions BaCu will precipitate and OH- and NO3- are spectator ions Cu(OH)2 will precipitate and Ba2+ and NO3- are spectator ions ONo precipitant will form

Explanation / Answer

Answer:-

Cu(NO3)2 will precipitate and Ba2+ and NO3- are spectator ions.

Because the solubility product of Cu(OH)2 and metal salt of nitrate is soluble.

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