I need number 1, both a & b answered. SYNTHESIS OF ETHYL CINNAMATE BY WITTIG REA
ID: 1040924 • Letter: I
Question
I need number 1, both a & b answered.SYNTHESIS OF ETHYL CINNAMATE BY WITTIG REACTION POSTLAB QUESTIONS answer directly on the sheets provided Calculate the theoretical yield for the reaction (must be g, not moles). Show the calculation. Make sure to do the following: use the actual masses you recorded, not the amounts suggested in the module; use the correct units in all calculations; use significant figures correctly in all calculations. l a. Calculate the percent yield for the reaction. Show the calculations. Make sure to use the correct units in this calculation; use significant figures correctly. Percent yield calculations should be done using masses, not moles! b.
Explanation / Answer
Molar Mass of benzaldehyde = 106 g
Molar Mass of CH2Cl2 = 85 g
no. of moles of benzaldehyde used = 0.255/106 = 0.00240 moles
Molar Mass of ethyl cinnamate = 176 g
Yeild if 100 percent completion of reaction = x
If 1 mole of benzaldehyde gives 1 mol of ethyl cinnamate
then 0.0024 mols of benzaldehyde gives or should give 0.0024*176 = 0.422
Thus theoretical yeild is 0.422 g
Mass of Product or Yeild = 0.337g
Yeild % = Yeild (g)/ Yeild if 100% completion (g) * 100
= 0.337*100/0.422
=79.8%(rounding off to 3 significant digits)