MasieringChernislry: Geded Homework #10-Sp 18 . Microsoft Edge https://session.m
ID: 1041168 • Letter: M
Question
MasieringChernislry: Geded Homework #10-Sp 18 . Microsoft Edge https://session.masteringchemistry.com/myct/itemView?assignmentProblemID-100728367 Graded Homework #10-Sp18 Item 1 1 of 20 > Constants I Periodic Table ? Part A Adrenaline is the hormone that triggers the release of extra glucose molecules in times of stress or emergency. A solution of 0.64 g of adrenaline in 36.0 g of CC14 elevates the boiling point by 0.49 °C. For carbon tetrachloride ( CCl), K 5.02 C/m Calculate the approximate molar mass of adrenaline from this data. Express your answer to two significant figures and include the appropriate units. Molar mass = alue Submit Provide Feedback Next > Adrenaline Type here to search ???Explanation / Answer
use:
? Tb = Kb*mb
0.49 = 5.02 *mb
mb= 0.0976 molal
m(solvent)= 36.0 g
= 3.6*10^-2 kg
use:
number of mol,
n = Molality * mass of solvent in Kg
= (9.761*10^-2 mol/Kg)*(3.6*10^-2 Kg)
= 3.514*10^-3 mol
mass(solute)= 0.64 g
use:
number of mol = mass / molar mass
3.514*10^-3 mol = (0.64 g)/molar mass
molar mass = 1.8*10^2 g/mol
Answer: 1.8*10^2 g/mol