CH 09 HW - Microsoft Edge session masteringchemistry.com myct itemView?assignmen
ID: 104297 • Letter: C
Question
CH 09 HW - Microsoft Edge session masteringchemistry.com myct itemView?assignmentProblemID:90738342&offset.ne; t CHALOY ± Limiting Reactant and Yield Mole Calculations Limiting Reactant and Yield: Mole Calculations Part A When exposed to air, aluminum metal, Al reacts with axygen, O,, to produce a protective costing of aluminum oxide, AlOs, which prevents the sluminum from rusting underneath. The balanced reection is shown here what is the theoretical yield of alum numaode 3 20 mol of alumnum metal is exposed to 270 mlr aoorr Express your answer with the appropriate units Hints IA Submit My Anseers Give Up Part BExplanation / Answer
From equation
4 mol Al = 3 MOL o2 = 2 mol Al2O3
NO OF mo of al = 3.2 mol
no of mol of O2 = 2.7 mol
limiting reactant = Al
no of mol of Al2O3 formed = 3.2*2/4 = 1.6 mol
Theoretical yield of Al2O3 = 1.6*102 = 163.2 grams