Charles\'s Law: a.) A sample of krypton gas at a pressure of 1.02 atm and a temp
ID: 104384 • Letter: C
Question
Charles's Law:
a.) A sample of krypton gas at a pressure of 1.02 atm and a temperature of 167 oC, occupies a volume of 587 mL. If the gas is heated at constant pressure until its volume is 849 mL, the temperature of the gas sample will be __________oC.
b.) A sample of methane gas at a pressure of 683 mm Hg and a temperature of 79 oC, occupies a volume of 13.4 liters. If the gas is cooled at constant pressure to a temperature of 29 oC, the volume of the gas sample will be __________L.
c.) A sample of helium gas at a pressure of 1.06 atm and a temperature of 169 oC, occupies a volume of 836 mL. If the gas is heated at constant pressure until its volume is 1.13 x 103 mL, the temperature of the gas sample will be __________oC.
Explanation / Answer
a)
we have:
T1 = 167.0 oC
= (167.0+273) K
= 440 K
V1 = 587 mL
V2 = 849 mL
we have below equation to be used:
V1/T1 = V2/T2
587.0 mL / 440.0 K = 849.0 mL / T2
T2 = 636.3884 K
T2 = 363 oC
Answer: 363 oC
b)
we have:
V1 = 13.4 L
T1 = 79.0 oC
= (79.0+273) K
= 352 K
T2 = 29.0 oC
= (29.0+273) K
= 302 K
we have below equation to be used:
V1/T1 = V2/T2
13.4 L / 352.0 K = V2 / 302.0 K
V2 = 11.5 L
Answer: 11.5 L
c)
we have:
T1 = 169.0 oC
= (169.0+273) K
= 442 K
V1 = 836 mL
V2 = 1130 mL
we have below equation to be used:
V1/T1 = V2/T2
836.0 mL / 442.0 K = 1130.0 mL / T2
T2 = 597.4402 K
T2 = 324 oC
Answer: 324 oC