Ch 181 HW 9: Solutions Name Class: Note: Please show calculations to get full cr
ID: 1043877 • Letter: C
Question
Ch 181 HW 9: Solutions Name Class: Note: Please show calculations to get full credit 1. Which would most likely not dissolve in water: a. ethanol b. acetone c. hexane d. KBr 2. Which compound forms an electrolyte solution when dissolved in water a. KCI b. Br2 C. CH, OH d. C H12 Os (glucose) 3. Gases are more soluble in liquid at a. lower pressure b. higher temperature c. lower pressure and lower temperature d. higher pressure and lower temperature 4. What is the mass percent concentration of a solution containing 25.0 g NaCl and 155 mL of water? Assume a density of 1.00 g/mL for water a. 2.76 % b. 6.20 % c. 13.9% d.16.1%Explanation / Answer
1) c.hexane
ethanol acetone are partially soluble in water due to presence polar functional group. KBr is completely soluble in water since it is an ionic compound.
So, insolube compoundis hexane since its completely non-polar compound.
2) a.KCl
Because KCl is the only ionic ompound among the given.
3) d.higher pressure and lower temperature
4) c.13.9%
mass of water = v x d = 155 mL x 1.00 g/mL = 155 g
mass of NaCl = 25 g
Mass of solution = 155 + 25 = 180 g
% mass of solution = mass of NaCl / mass of solution X 100
% mass of solution = 25 / 180 x 100 = 13.9%
5) d. 1.95 g
mass of the solution = d x v = 1.03 g/mL x 58.2 mL = 59.9 g
% mass glucose = 3.25 %
% mass glucose = mass of glucose / mass of solution x 100
3.25 = mass of glucose / 59.9 x 100
mass of glucose = 1.95 g
6) b.0.390 M
Molarity = moles / volume(L)
moles of Ca(NO3)2 = mass / molar mass = 11.2 / 164.08 = 0.0682 mol
volume = 175 mL = 0.175 L
Molarity = 0.0682 / 0.175 = 0.390 M