I need help with the number 2 and 3 and can someone check my work Chem 407 (Bioc
ID: 1043890 • Letter: I
Question
I need help with the number 2 and 3
and can someone check my work
Chem 407 (Biochemistry D) Exam II (3/19/2018) Name: . (22 pts) Answer each of the following questions by choosing the right number below. ( RFLPs (5) intron (9) concerted model semiconservative 6) sickle-cell anemia (3) hyperchromicity (genetic code (4) P (8) Bohr ef 0) Southern blottir (tý restriction enzymes (a) The symmetry of the subunits are maintained - (b) A variation in the DNA sequence of a genome that can be detected by breakin pieces and analyzing the size of the resulting fragments by gel electrophoresis. 1 () used by certain bacteria to block phage infections 2d) The nucleotide sequence within a gene that is removed by during the RNA L (e) DNA replication produces two copies that each contained one of the origina entirely new strand. () mutations in genes encoding hemoglobin (g) If the sequence of at least part of a DNA segment is known, the segment c this method. 22 (h) CO2 and H" on the oxygen binding curve () Separates and identifies a specific DNA fragment. LL G) The relationship between the sequence of bases in DNA (or RNA transcr sequence of amino acids in proteins. (k) Increase of UV absorption upon denaturation of DNA duplex. 2. (6 pts, No partial credit) An autoradiogram of a sequencing gel containi fragments is shown below. What is the sequence of the DNA fragment? (5" toExplanation / Answer
3) a) false as it is B form helix
c) true it is known as semiconservative nature
d) false optical density increases when nucleotides are in single stranded form which indicate they absorb UV more in single stranded form than in double stranded
e) true as many polymerase have 5' - 3' and 3' - 5' exonuclease activity.3'- 5' exonuclease activity is known as proof reading activity also
f) false transcription begins from promoter and ends at terminator while translation begins at the start codon and terminate at stop codon
g) false because post translation modification takes place in eukaryotes as glycosylation
h) true.