Predict the products of the following acid-base reactions, and predict whether t

Question

Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the reaction arrow.

Part A

O2?(aq)+H2O(l)?

Express your answer as part of a chemical equation. Identify all of the phases in your answer.

Part B

Predict whether the equilibrium lies to the left or to the right of the equation in previous part.

Part C

CH3COOH(aq)+HS?(aq)?

Express your answer as part of a chemical equation. Identify all of the phases in your answer.

H2S(aq)+C2H3O2?(aq)H2S(aq)+C2H3O2?(aq)

Part D

Predict whether the equilibrium lies to the left or to the right of the equation in previous part.

Part E

NO2?(aq)+H2O(l)?

Express your answer as part of a chemical equation. Identify all of the phases in your answer.

Part F

Predict whether the equilibrium lies to the left or to the right of the equation in previous part.

O2?(aq)+H2O(l)? OH?(aq)+OH?(aq)

Explanation / Answer

Part A)

reaction,

O2(aq) + 2H2O(l) + 4e- <==> 4OH-(aq)

Part B)

The equilibrium for the reaction in Part A lies on the ,

H2O is a stronger acid than OH-, so the equilibrim lies on the right

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Part C)

reaction,

CH3COOH(aq) + HS-(aq) <==> CH3COO-(aq) + H2S(aq)

Part D),

The equilibrium for Part C lies on,

CH3COOH is a stronger acid than H2S, so the equilibrium lies on the right

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Part E)

reaction,

NO2-(aq) + H2O(l) <==> HNO2(aq) + OH-(aq)

Part F)

The equilibrium for the Part E lies on the,

HNO2 is a stronger acid than H2O, so the equilibrium lies on the left.

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