Meoneramett1 Core Chemistry Skil: Using the Ideal Gas LBW previoue | 18 of 23 |
ID: 104506 • Letter: M
Question
Meoneramett1 Core Chemistry Skil: Using the Ideal Gas LBW previoue | 18 of 23 | nest ± Core Chemistry Skat Usng the Ideal Gas Law baloon 5 floating around outside your w dow. The tempe ture outside LB oC and the ar pressure 5 balloon? Express your answer to three signiticant figures and include the appropriate units. Hints a m Your neighbor, who released the baloon tels you that he filed it with 4.00 mole of gas what the vo me of gas node tho Learning Goal To apply the deal gaa law so poblams involving temperature. pressure. volume. and moles of a gas. The four properties of gases (pressure P volume V, comperature T, and moles of ga: are related by a single expression known as the ideal gs The variable R is known as the universal gas constent and has R-0.0821 L atm/(mole·K). The units of R dietate the units for all other quanttes, so when using this value of R, use units of atmaspheres for pressure, liters for volume, and kelvins for temperature. Part B A 18.0 L gas cyinder filed with 5.40 moles of g25. The tank s tored at 9·C·What Express your answer to three significant figures and include the appropriate units the pressure the tric? Pan-Value Units Part C 120 L klis used for vitrifying o amics. It is currently operating 81 545 °C and the pressure Express your answer to three signficant figures and inelude the appropriate units 0.9500 atm Hog many moles of sir molecules are within he confines of the kin? aaleUnits Part D A 200 L. gas cyänder has been fiaed with 4.00 oles of gas. You measure the pressure to be 3.00 atn, what is the temperature irside the tank? Expre“ your answer to three significant figureG and include the appropriate units.Explanation / Answer
A)
we have:
P = 0.7 atm
n = 4.00 mol
T = 9.0 oC
= (9.0+273) K
= 282 K
we have below equation to be used:
P * V = n*R*T
0.7 atm * V = 4 mol* 0.08206 atm.L/mol.K * 282 K
V = 132.2338 L
Answer: 132 L
B)
we have:
V = 18.0 L
n = 5.40 mol
T = 9.0 oC
= (9.0+273) K
= 282 K
we have below equation to be used:
P * V = n*R*T
P * 18 L = 5.4 mol* 0.08206 atm.L/mol.K * 282 K
P = 6.94 atm
Answer: 6.94 atm
C)
we have:
P = 0.95 atm
V = 120.0 L
T = 945.0 oC
= (945.0+273) K
= 1218 K
find number of moles using:
P * V = n*R*T
0.95 atm * 120 L = n * 0.08206 atm.L/mol.K * 1218 K
n = 1.141 mol
Answer: 1.14 mol
D)
we have:
P = 3.5 atm
V = 20.0 L
n = 4.00 mol
we have below equation to be used:
P * V = n*R*T
3.5 atm * 20 L = 4 mol* 0.08206 atm.L/mol.K * T
T = 213.2586 K
Answer: 213 K