Part A The heat capacity of an object indicates how much energy that object can

Question

Part A The heat capacity of an object indicates how much energy that object can absorb for a given increase in that object's temperature. In a system in which two objects of different temperatures come into contact with one ancther, the warmer object will cool and the cooler object will warm up until the system is at a single equilibrium temperature. A volume of 125 mL of HH20 is initially at room temperature (22.00C). A chilled steel rod at 2.00 C is placed in the water. If the final temperature of the system is 21.10 °C , what is the mass of the steel bar? Use the following values: Note the difference between the terms molar heat capacity, which has units of J/(mol·°C), and specific heat, which has units of specific heat of water 4.18 J/(g.°C) specific heat of steel 0.452 J/(g. °C) Express your answer to three significant figures and include the appropriate units. View Available Hints) HA mass of the steelValue Units Submit Part B The specific heat of water is 4.18 J/(g. C). Calculate the molar heat capacity of water. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) molar heat capacity for waterValue Units Submit

Explanation / Answer

part A

heat lost by water = heatgained by Fe bar

mass of water(m1)*C1*DT = m2*C2*DT2

125*4.18*(22-21) = m2*0.452*(21-2)

m2 = mass of Fe = 60.8 g

part B

molarheat capacity(c) = s*mWT

S = specific heat of water = 4.184 j/g.c

Mwt = molarmass of water = 18 g/mol

C = 4.184*18 = 75.3 j/mol.c

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---