Sulfur and fluorine react to form sulfur hexafluoride according to the reaction

Question

Sulfur and fluorine react to form sulfur hexafluoride according to the reaction shown here. How many moles of F2 are required to react completely with 2.55 ML of s? s(s)+3f2(g)->sf6(g) ssessment8.1 Constants I Periodic Ta Part A Sulftur and fuorine react to form sulfur hexafluoride according to the reaction shown here. How many moles of Fa are required to react completely with 2 55 mol of S? S(o)+3P (o)+SF(a) 15.3 mol F O 2.55 mol F2 7.65 mol F O 1275 mol F2 Submit Provide Feedback Next > search SAMSUNG

Explanation / Answer

The balanced reaction is:
S(s) + 3 F2 (g) —> SF6 (g)

From reaction,
mol of F2 = 3*number of moles of S
= 3*2.55 mol
= 7.65 mol

Answer: 7.65 mol

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