Perform the following metric system conversions: 205 kg = g 62.2 mu m = nm 87 K

Question

Perform the following metric system conversions: 205 kg = g 62.2 mu m = nm 87 K = degree C 9017 mL = ML 272 degree C = k Perform the following conversions to or from scientific notation (use correct significant figures): 1.05 times 10^4 = 1.05 times 10^-5 = .0870 = .0000901 = 20600 = Complete the following: Discuss the meaning of the zigzag line with respect to metals, nonmetals, post transition elements, metalloids, etc. Calculate the mass of 1.5 times 10^24 molecules of bromine gas. Calculate the mass percent of each element in silver dichromate.

Explanation / Answer

3. Metric conversion

a) 205 kg x 1000 g/1 kg = 205000 g

b) 62.2 um x 1000 nm/1 um = 62200 nm

c) 87 K - 273 = -186 oC

d) 9015 ml x 1L/1000 ml = 9.015 L

e) 272 oC + 273 = 545 K

4. Scientific conversions

a) 1.05 x 10^4 = 1050

b) 1.05 x 10^-5 = 0.0000105

c) 0.0870 = 8.70 x 10^-2

d) 0.0000901 = 9.01 x 10^-5

5. Complete details

Isotope : I-127

Symbol : 127I53

Mass number : 127

Protons : 53

Electrons : 53

Neitrons : 74

13. Zig-zag line refers to the inconsistency in properties of metal, non-metla, metalloids etc. The property cannot be defined in terms of a fixed property when the line is such.

14. Mass of Br2 = (1.5 x 10^24/6.023 x 10^23) x 79 = 196.746 g

15. Mass percentage of elements in Ag2Cr2O7

molar mass = 431.7244 g

mass % Ag = 2 x 107.8686 x 100/431.7244 = 49.97%

mass % Cr = 2 x 52 x 100/431.7244 = 24.09%

mass % O =  7 x 16 x 100/431.7244 = 25.94%

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