Combustion of hydrocarbons such as methane (CH_4) produces carbon dioxide, a \"g

Question

Combustion of hydrocarbons such as methane (CH_4) produces carbon dioxide, a "greenhouse gas". Greenhouse gases in the Earth's atmosphere can trap the Sun s heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide. Write a balanced chemical equation, including physical state symbols, for the combustion of gaseous methane into gaseous carbon dioxide and gaseous water. Suppose 0.230 kg of methane are bunted in air at a pressure of exactly 1 atm and a temperature of 12.0 degree C. Calculate the volume of carbon dioxide gas that is produced. Round your answer to 3 significant digits.

Explanation / Answer

2A)

CH4(g)    + 2O2(g)   _---------> CO2(g)  + 2H2O(g)

b) According to this equation 1 mole of methane on burning in oxygen produces 1 mole of CO2

Weiight of methane = 0.230Kg = 230g

moles of methane = 230/16 =14.375 moles

According to stoichiometry, the number of moles of CO2 formed = 14.375

Temperature of reaction = 12 C = 273+12 = 285 K

pressure of the reaction = 1 atm

Now AT STP 1 mole of CO2 occupies 22.4L volume (T=273K, P= 1 atm)

the volume occupied by 14.375 moles at STP = 14.375 x 22.4 L

At 285 K , the volume ocupies is given by P1V1/T1 = P2V2/T2

1atm x 14.375 x 22.4 / 273 = 1 atm x V /285

Thus the volume of CO2 produced at 12 C = 336.153 L

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