Consider the complexes shown below. For the six coordinate complexes, draw the p

Question

Consider the complexes shown below. For the six coordinate complexes, draw the possible d electron configurations (high spin vs. low spin) in an octahedral ligand field. For the four coordinate complexes, draw the configurations for tetrahedral and square-planar ligand fields. Calculate the expected spin-only magnetic moment (pso) for each of the configurations and determine the correct ground state by comparison with the experimentally determined values. Aside from experimental error, which effect not included in the spin-only approximation could account for the observed deviation? Determine the orbital degeneracy (non-degenerate, doubly degenerate or triply degenerate) of the ground state and correlate it to the observed deviations from spin-only behavior. What trend can you observe?

Explanation / Answer

[Co(NH3)6]^2+ Co(II) high spin. number of unpaired electrons = 3

spin only magnetic moment =n(n+2) = 3*5 =3.87

ground state is t2g^5 eg^2

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[Co(F)6]^3-

Co(III) low spin. number of unpaired electrons = 4

spin only magnetic moment =n(n+2) = 4*6 =4.9

ground state is t2g^4 eg^2

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[CoCl4]^2-

Co(II) high spin. number of unpaired electrons = 3

spin only magnetic moment =n(n+2) = 3*5 =3.87

ground state is e^4 t2^3

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[Cr(H2O)6] ^3+

Cr(III) d^3 configaration.

number of unpaired electrons = 3

spin only magnetic moment =n(n+2) = 3*5 =3.87

ground state configuration: t2g3 eg0

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Pt(NH3)2(Cl)2 d^8 square planar complex

number of unpaired electron = 0, spin only magnetic moment = 0

ground state congiguration : dxy,dx2-y2 (4) , dxz, dyz(4) dz^2(0)

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[Fe(CN)6]^3-

low spin Fe(III), d^5 configuration.

number of unpaired electrons = 1

spin only magnetic moment =n(n+2) = 1*3 = 1.73

ground state : t2g5 eg0

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[Fe(H2O)6]^2+

high spin Fe(II), d^6 configuration.

number of unpaired electrons = 4

spin only magnetic moment =n(n+2) = 4*6 = 4.9

ground state : t2g4 eg2

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[Mn(H2O)6]^2+

high spin Mn(II), d^5 configuration.

number of unpaired electrons = 5

spin only magnetic moment =n(n+2) = 5*7 =5.9

ground state : t2g3 eg2

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