Identify the conjugate base of HSO_4^- H_2SO_4 H_2SO_3, SO_4^2- H_2O OH^- A rate
ID: 1066705 • Letter: I
Question
Identify the conjugate base of HSO_4^- H_2SO_4 H_2SO_3, SO_4^2- H_2O OH^- A rate constant for a particular reaction is 0.0090 s^-1. What is the overall order of this reaction? 1 4 0 2 3 The reaction 2SO_3(g) leftharpoonoverrightharpoon 2SO_2(g) + O_2(g) is endothermic. If the temperature is increased. Is no change will occur in K_c. the pressure will decrease. K_c will increase. K_c will decrease. More SO_3 will be produced. In general, which of the following types of solids would be the most soluble in carbon disulfide, CS_2? metallic nonpolar molecular network covalent ionic polar molecular For which of the following reactions are the numerical values of K_p and K_c the same? 1.2SO_2(g) + O_2(g) leftharpoonoverrightharpoon 2SO_3(g) N_2(g) + O_2(g) leftharpoonoverrightharpoon 2NO(g) H_2(g) + I_2(g) leftharpoonoverrightharpoon 2HI(g) 1 and 2 only 1 only 1, 2, and 3 2 only 2 and 3 only Which one of these salts will form a neutral solution on dissolving in water? NaCN NH_4NO_3 KNO_2 FeCl_3 NaCl For the following reaction at equilibrium, which change will cause the equilibrium to shift to the left? 2NOBr(g) leftharpoonoverrightharpoon 2NO(g) + Br_2(g), delta H degree _rxn = 30 kJ/mol Remove some Br_2. Increase the container volume. Add more NOBr. Decrease the temperature. Rome some NO.Explanation / Answer
1. Accoding to the conjugate acid base pair theory, the conjugate base of an acid has one proton less than the parent acid.
So, the conjugate base of HSO4- is SO42-.
Therefore, the correct answer is option C.
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2. The rate constant of a reaction is 0.0090 s-1. The units of the rate constant indicate the order of a reaction.
s-1 are the units of a first order reaction.
Therefore, the correct answer is option A.
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3) According to the Le Chateliers principle, if the equilibrium is disturbed by changing the conditions, then the position of equilibrium will move in that direction so as to counteract that change.
Since, the reaction is endothermic, increasing the temperature of the reaction will shift the position of the equilibrium towards the formation of the products. As the product formation increases, the equilibrium constant Kc increases.
Therefore, the correct answer is option C.
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4) Like dissolves like.
Since, CS2 is a nonpolar molecule, nonpolar molecular sloids are most soluble in it.
Therefore, the correct answer is option B.