To find the equilibrium constant K at 500 K if K at 298K is known, the best form

Question

To find the equilibrium constant K at 500 K if K at 298K is known, the best formula to use it DeltaG_0 = (-) RT InK ln(K_2/K_1) = Delta H/R(1/T_1-1/T_2) ln K = V/RT(p-1) K = r.m(M/1000) Naphthalene (C_10H_8) melts at 78 degree C, 1.00 atm pressure. The density of solid naphthalene is 0.85 grams per ml, while the density of liquid naphthalene is 0.80 grams per mL Delta H of fusion for naphthalene is 19.1 KJ per mole. If 100 atm of pressure is applied, what would be the melting point of naphthalene?

Explanation / Answer

To fine the equilibrium constant K at 500 K if K at 298 K is known , the best formula to use

a) G° = -RTlnK:.

b) ln(K2/K1) =rH /R   (1/T1 -1/T2---------------)-answer

C) LnK =V/RT(P-1)

D)K=T.m(M/1000)

The equilibrium constant varies with temperature according to the van’t Hoff equation:

ln(K2/K1) =rH /R   (1/T2 -1/T1)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---