Consider the following second order chemical reaction: 2X + Y rightarrow W + 3Z
ID: 1068957 • Letter: C
Question
Consider the following second order chemical reaction: 2X + Y rightarrow W + 3Z Which of the following changes would alter the rate constant (k) for the reaction? Increasing the temperature of the reaction Increasing the concentration of X Increasing the concentration of Z Decreasing the concentration of Y Decreasing the concentration of W If the reactant X is found to be disappearing at a rate of 6.2 times 10^-4 M/s, what is the rate of formation for the product Z? 1.9 times 10^-3 M/s 2.7 times 10^-4 M/s 4.1 times 10^-4 M/S 9.3 times 10^-4 M/S Which of the following represent a reasonable rate law for this second order reaction? Rate = k[X]^2[Y] Rate = k[X][Y]^2 Rate = k[W][Z]^3 Rate = k[W][Z] Rate = k[Y]^2 If you have concentration and time data for this reaction, which of the following plots would give you a linear slope, thus confirming that the reaction is in fact second order. In [X] vs time [X] vs time [X]^2 vs time [X]^-1 vs time consider the curve shown to the right. The curve shown represents an ___________ reaction with an enthalpy (delta H) of _________________. Endothermic, +5 kJ/mol Endothermic, + 4 kJ/mol Exothermic, -5 kJ/mol Exothermic, -4 kJ/mol If a catalyst is added to the chemical reaction, the new activation energy will be ____________. above 9 kJ/mol equal to 9 kJ/mol between 1 kJ/mol and 5 kJ/mol between 4 kJ/mol and 9 kJ/molExplanation / Answer
11 - ans is A ; rate constant depends on Temperature so increasing temp, rate wl be increased.
12 ans C; 2 mol of X will gives 3 moles of Z.
If x decreasing 6.2*10-4 rate, then the rate of W formation wl be 6.2*10-4(2/3) equal to 4.1 * 10-4
13 ans is D ; two (different) reactants involves in the second order rate reaction
14 ans is D ; 1/X vs time gives linear line
15 ans is B; products have more energy than reactants so endothermic; energy diff is 5-1 = 4 kJ/mol
16 ans is D; by adding catalyst, the activation energy will be reduced but the final product energy wont change. SO the option C is invalid. But the activation energy will be less thN FIRST REACTION THAT MEANS 9 kJ/mol and above the products energy that means 4 kJ/mol