In the experiment described in question 1 (reprinted below), it is later determi
ID: 1070101 • Letter: I
Question
In the experiment described in question 1 (reprinted below), it is later determined that the balance used to determine the mass was fault). The balance gave a reading that was always 2.34 higher than the actual mass. a. Given this fact, first adjust the data and report the corrected values in the left table above. Show a sample calculation of this below. b. Now, re-analyze the now corrected data from question 1 (selecting the either all data or only five trials due to use of 3s rule as appropriate) to determine the mean mass and standard deviation in the mass. Show your work as before.Explanation / Answer
since the balance gives a higher value than actual mass, actual mass= mass read by balance-2.34
average mass = sum of actual masses/number of samples
standard deviation =
the calculation are shown below.
Mass ( as measured by Balance) Errror Actual mass (gm) (mave-m) (mave-m)2 23.45 2.34 21.11 0.026666667 0.000711111 24.62 2.34 22.28 -1.143333333 1.307211111 21.92 2.34 19.58 1.556666667 2.423211111 22.95 2.34 20.61 0.526666667 0.277377778 20.12 2.34 17.78 3.356666667 11.26721111 23.12 2.34 25.46 -4.323333333 18.69121111 Average( mave) 21.13666667 33.96693333 5.661155556 standard deviation 2.379318296