Complete the following sentence. A scientific law is: a tentative explanation fo

Question

Complete the following sentence. A scientific law is: a tentative explanation for a set of observations that can be tested try further. Experimentation a statement describes a relationship between phenomena that is always the same under the same conditions. a unifying principle that explains a body of facts and relations. a modal used to visualize the invisible. The diameter of the mucous of an atom is approximately 1 times 10^-15 meters. If t is equal to 10 Angstroms, what is the diameter of the nucleus in Angstroms? 1 times 10^2-3 A 1 times 10^-8 A 1 times 10^-7 A 1 times 10^-5 A A gold ingot weights 5.00 lbs. If the density of gold is 19.31 g/cm^3, and the length and width of the ingot are 12.0 cm and 4.00 cm respectively. What is the height of the ingot? 6.50 times 10^-3 Cm 3.59 cm 10.2 cm 2.45cm A student measured the diameter of sphere and determined the average value. His measurements are 5.17 cm. 5.16 cm. 5.16 cm. and 5.17 cm. If the true diameter is 6.18 cm. What can be said about the student's results? It is accurate and precise. It is accurate but not precise. It is precise but not accurate. It is neither precise nor accurate. What is the de Broglie wavelength of an electron (m = 9.11 times 10^31 kg) moving at a velocity of 3.0 times 10^7 m/s? de Broglie equation: lambda = h/mv. where Planck's constant, h = 6.626 times 10^-34 Kg m^2/s. less than 3.9 times 10^-12 m 2.4 times 10^-11 m 3.3 times 10^-8 m greater than 1.1 times 10^-4 m

Explanation / Answer

Ans 1 - Option B

Ans 2 - Option D

as diameter of nucleus is 1x10-15m converting it into angstroms

=(1x10-15 x10)/1x10-9 =1x10-5 A0

Ans 3 -Option D

1lb=0.45kg so weight of ingot is = 5x0.45=2.26kg=2268g

volume of ingot is= weight/density=2268/19.31=117.45cm3

Volume=length x width X height

so Height of ingot is = 117.45/(12x4) = 2.45cm

Ans 4 - Option D

Ans 5 - Option B

Lambda = h/mv

So De Broglie wavelength of an electron lambda =6.626x10-34/(3x107x9.11x10-31) = 2.4x10-11m

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