Consider the following situation: A + BC + D if 5 moles each of A and B are mixe
ID: 1075374 • Letter: C
Question
Consider the following situation:
A + BC + D
if 5 moles each of A and B are mixed with 10 moles of C, which of the following describes what will happen?
a) C will react to form A and B, because there are more moles of C intially
b) A and B will react to make C and D, no matter what the value of Keq
c) A and B will react to form C and D, but only if Keq is large.
d) No reaction will occur - there are 10 moles each of reactants and products, so the reaction is at equilibrium.
Much help would be appreciated :) Thanks!
Explanation / Answer
Answer is option A
C will react to form A and B because there are more moles of C intially
Reason behind this is Le Chatelier principle
According to this, If cocncentration increase either on left or right side of the equation the equilibrium will shift according to that and maintain equilibrium constant.