Part A The ideal gas lw (P-nRT) describes the relationship among pressure P, vol

Question

Part A The ideal gas lw (P-nRT) describes the relationship among pressure P, volume V, temperature T, and molar amount n. When some of these variables are constant the ideal rearranged in different ways to take the following forms where k is a constant A certain amount of chlorine gas was placed inside a cylinder with a movable piston at one end. The initial volume was 3.00 L and the initial pressure of chlorine was 1.70 atm. The piston was pushed down to change the volume to 1.00 L. Calculate the final pressure of the gas if the tempereture and number of moles of chlorine remain constant. (Figure 1) gas law can be Express your answer with the appropriate units. Name Boyle's law P TRT- Charles's law Expression Constant and T View Avallable HInt s) Avogadro's law n- = k | T and P PtnalValue Units Submit Part B gure 1of 1 In an air conditioned room at 19.0 °C, a spherical balloon had the diametr of 50.0 cIm When taken outside on a hot sumer day, the balloon expanded to 51.0 cm in diameter, what was the temperature outside in degrees Celsius? Assurne that the balloon is perfect sphere and that the pressure and number of moles of air molecules remains the same. Express your answer with the appropriate units. View Available Hint(s) V-3.00 L V=1.00 L outside temperatureValuUnils

Explanation / Answer

A)
Given:
Pi = 1.70 atm
Vi = 3.00 L
Vf = 1.00 L

use:
Pi*Vi = Pf*Vf
1.70 atm * 3.0 L = Pf * 1.0 L
Pf = 5.10 atm
Answer: 5.10 atm

B)
we need to use V/T = constant
V of sphere = (4/3)*pi*r^3 = (4/3)*pi*(d/2)^3
where d is diameter

The new expression to be used will be:
d^3/T = constant

we have:
d1 = 50.0 cm
d2 = 51.0 cm
T1 = 19.0 oC = (19.0+273) K = 292 K

use:
d1^3/T1 = d2^3/T2
50.0^3/292 = 51.0^3/T2
T2 = 310 K
= (310-273) oC
= 37 oC
Answer: 37 oC

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---