Answer options are as follows: 1. -isotonic, hypertonic, hypotonic 2. the same,

Question

Answer options are as follows:

1. -isotonic, hypertonic, hypotonic

2. the same, higher, lower

3. Side A, Side B

4. glucose, sucrose, glucose and sucrose

Consider the solutions in the arms of this U-tube. The solutions are separated at the bottom of the tube by a selectively permeable membrane (dashed vertical line). This membrane is permeable to water and glucose, but not permeable to sucrose. Before diffusion begins the solutions are of equal volume and the concentrations of sucrose and glucose on each side of the membrane are as indicated in the figure. 1 M sucrose 2 M sucrose 2 M glucose 1 M glucose At the beginning of the experiment, before diffusion begins, the solution in side A with respect to side B is__. After the system reaches equilibrium, the concentration of glucose in side A, relative to side B, will be After equilibrium is reached, the water level will be higher in the U-tube in Which solute(s) will exhibit a net movement across the membrane?

Explanation / Answer

Q1. Isotonic

Q2. The same

Q3. Side B

Q4. Glucose

Here, glucose and water can freely move across the membrane, but sucrose cannot. So, to bring the concentration of glucose equal, glucose will go from side A to side B, taking water along with it, causing the level of side B to rise.

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