Question 16 1 pts Question 18 1 pts Calcium sulfate is only sparingly soluble. I

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Question 16 1 pts Question 18 1 pts Calcium sulfate is only sparingly soluble. If 1.0 M HCl is added to an equal volume of 1.0 M NaOH, what are the new concentrations of OH and H3O? CaSO4(s) Ca2(ag)+SO2(aq) If Ks-3.2x 10-6, when an excess of the solid is dissolved in water what is the maximum concentration of Ca2 (aq) in mol L1? 0 [H30.]-1.0 x 10.7 M, [OH')-10 x 10.7 M Give your answer to sufficient significant figures and do not include the units in the answer box. Hint: to help answer this question, first work out the mathematical equation for K in terms of the concentrations of the chemical species.) o [H3O*) _ 0.5 M. [OH']-0.5M [H301-1.0 M, (OH]-1.0M o [H3O+] . 2.0 M. [OH). 2.0 M

Explanation / Answer

answer 16.)

For this reaction, each mole of CaSO4 that dissolves produces 1 mole of both Ca2+ and SO42-. The solubility would then equal the concentration of either the Ca2+ and SO42-ions.

solubility = [Ca2+] = [SO42-]
M = [Ca2+] = [SO42-]

Ksp = [Ca2+][SO42-]
Ksp = M x M
Ksp =M2

3.2 x 10-6= M2

M = 1.8 x 10-3 molL-1

answer 18.)

Adding an additional 1M of strong base to the solution will correspond to a complete neutralization.

All the moles of hydronium cations that were initially present in the solution are now completely consumed. The resulting solution is neutral since it only contains water and aqueous sodium chloride.

The concentration of hydronium cations corresponds to that of pure water at room temperature, 1.0 x 107M.

so, first option is correct. both have same concentration that is 1.0 x 107M.

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