Consider a situation where an individual rolls a six-sided die with possible out

Question

Consider a situation where an individual rolls a six-sided die with possible outcomes being 1, 2, 3, 4, 5, and 6, and records their score, and calculates their average score as the the total of all their scores divided by the number of throws. Say an individual has thrown a 1, 1, 2, and 3. 6.2.   What is the individual's average of their four throws of 1, 1, 2, and 3? Consider a situation where an individual rolls a six-sided die with possible outcomes being 1, 2, 3, 4, 5, and 6, and records their score, and calculates their average score as the the total of all their scores divided by the number of throws. Say an individual has thrown a 1, 1, 2, and 3.

Explanation / Answer

so basically here we have to calculate the average of the scores,

average = sum of scores/ no. of throws = 1+1+2+3/4 =7/4 = 1.75

so answer is 1.75

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