Hardy-Weinberg Problem. Please help?

Question

Okay, so this problem is talking about a groupof people (10,000). 13.32% have blood type AB; 23.04% have O; 37.8%have A; and 25.96% have B. From this I calculated the followingallelic frequencies:
I^A = .3
I^B = .22
i = .48

Now, for the next part, I'm supposed to assume that the populationhas increased to 25,000 people, and then give the new allelicfrequency. I'm supposed to use these later to find the newpopulation distributions, but I thought about it, and they didn'tgive me the percentages or anything. Am I supposed to assume theyare the same? And if so, won't the allelic frequency be the samewith 25,000 people as with 10,000?
Thank you in advance!!

(Please ask if you need any additional info, etc.)

(Also, I think my teacher made this up, so it wasn't in the book oranything.)
Okay, so this problem is talking about a groupof people (10,000). 13.32% have blood type AB; 23.04% have O; 37.8%have A; and 25.96% have B. From this I calculated the followingallelic frequencies:
I^A = .3
I^B = .22
i = .48

Now, for the next part, I'm supposed to assume that the populationhas increased to 25,000 people, and then give the new allelicfrequency. I'm supposed to use these later to find the newpopulation distributions, but I thought about it, and they didn'tgive me the percentages or anything. Am I supposed to assume theyare the same? And if so, won't the allelic frequency be the samewith 25,000 people as with 10,000?
Thank you in advance!!

(Please ask if you need any additional info, etc.)

(Also, I think my teacher made this up, so it wasn't in the book oranything.)

Explanation / Answer

I will   start the problem from the second part. Firstly for any population to be in Hardy-Weinberg Equilibrium theallele & genotype frequencies should remain   constant   from one generation to the next i.e. no evolution should    occur at the locus . As we   know  that   for   blood group allele I A   &  IB   are   codominant  &   both   are dominant  over i allele. Therefore   blood group A can be IAi    &   type B   can be IBi. As we   know  that   for   blood group allele I A   &  IB   are   codominant  &   both   are dominant  over i allele. Therefore   blood group A can be IAi    &   type B   can be IBi. For   any locus with three alleles the Hardy - Weinberg equilibrium is given   by ( p + q + r ) 2 =1                                                                          (1) p2 + q2 +r 2 + 2pq + 2pr + 2qr=1                                                (2) Here p , q , & r represent   the   allele  frequency of   I A I B   & i ( 2pq represents   genotype  frequency   of   I AIB) The   genotype frequency   for each group   is given   in equation (2) The population distribution   for each genotype can be calculated  by   multiplying each  genotype   frequency   by the population size , such that when adding all   the   individuals of each genotypes the answer should equal   the population size. For example ,taking from your calculation   the   allelic frequency for IA = 0.3 genotype   frequency for this allele is I A * IA= 0.3*0.3= 0.09 Total   number   of individuals with this genotype =0.09*25000=2250     .(Hope this  helps )

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