A recent study focused on the number of times men and women who live alone buy t
ID: 1247278 • Letter: A
Question
A recent study focused on the number of times men and women who live alone buy take-out dinner in a month. Assume that the distributions follow the normal probability distribution. The information is summarized below. Statistic Men Women Sample mean 25.73 22.50 Population standard deviation 5.76 4.69 Sample size 32 37 At the .01 significance level, is there a difference in the mean number of times men and women order take-out dinners in a month? Hint: Consider the "Men" data as the first sample. (a) Compute the value of the test statistic. (Round your answer to 3 decimal places.) (c) What is the p-value? (Round your answer to 4 decimal places.)Explanation / Answer
H0: m1 =m2
Ha: m1 ¹m2
Get the test statistic:
(25.73 - 22.50) / (5.762/32 + 4.692/37)
= 2.52
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The p value (from a table)
= 0.2067
This is well above the 0.01 significance, so we do not reject the null hypothesis.
There is no statistic difference.