In the figure, block 1 has mass m1 = 470 g, block 2 has mass m2 = 550 g, and the
ID: 1260973 • Letter: I
Question
In the figure, block 1 has mass m1 = 470 g, block 2 has mass m2 = 550 g, and the pulley s on a frictionless horizontal axle and has radius R = 4.6 cm. When released from rest, block 2 falls 74 cm in 5.3 s without the cord slipping on the pulley. (a) What is the magnitude of the acceleration of the blocks? What are (b) tension T2 (the tension force on the block 2) and (c) tension T1 (the tension force on the block 1)? (d) What is the magnitude of the pulley?s angular acceleration? (e) What is its rotational inertia? Caution: Try to avoid rounding off answers along the way to the solution. Use g = 9.81 m/s^2.Explanation / Answer
equation for block m1
T - m1 * g = m1a
equation for block m2
m2 * g - T = m2a
given,
m1 = 470 g
m2 = 550 g
Solving for T from above equations we get
T = 4.972 N
Tension T1 = 4.972 N
putting the value of T in the above mentioned equation
we get,
m2g - T = m2a
0.550 * 9.81 - 4.792 = 0.550 * a
a = 1.09 m/s^2
acceleration of the blocks = 1.09 m/s^2
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