The figure below shows a closed loop carrying a current of 2.00 A. The loop cons
ID: 1261913 • Letter: T
Question
The figure below shows a closed loop carrying a current of 2.00 A. The loop consists of a half circle of radius 4.15 m, two quarter circles of radii 2.05 m, and three radial straight wires. What is the magnitude of the net magnetic field at the common center of the circular sections?
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Explanation / Answer
B at center of a circle B = (uo*I*theta)/(4*pi*R)
Bnet = (uo*I*(pi/2))/(4*pi*R1) - (uo*I*(pi/2))/(4*pi*R1) + (uo*I*pi)/(4*pi*R2)
Bnet = (uo*I)/(4*R2)
Bnet = (uo*I)/(4*R2)
Bnet = 1.513*10^-7 T <,,,,---answer