QUESTION: A charge q 1 = 2.3 ? 10 -6 C is placed at the origin and charge q 2 =

Question

QUESTION: A charge q 1 = 2.3 ? 10-6 C is placed at the origin and charge q 2 = -5.5 ? 10-6 C is placed on the x-axis, at x = -0.20 m. Where along the positive x-axis can a third charge Q = -8.3 ?C be placed such that the resultant force on this third charge is zero?

Answer: Q @ (0.36,0), how do you get this answer?

QUESTION: A charge q 1 = 2.3 ½ 10-6 C is placed at the origin and charge q 2 = -5.5 ½ 10-6 C is placed on the x-axis, at x = -0.20 m. Where along the positive x-axis can a third charge Q = -8.3 ½C be placed such that the resultant force on this third charge is zero? Answer: Q @ (0.36,0), how do you get this answer?

Explanation / Answer

Here , for charge ,

q1 = 2.3 *10^-6 C

q2 = -5.5 *10^-6 C

Now , field is zero in the right of q1 ,

let the point be x

then for E1 = E2

k*q1/x^2 = k*q2/(x + 0.2)^2

2.3/x^2 = 5.5/(x+0.2)^2

solving for x

x = 0.36 m

hence , the force on q3 is zero at (0.36 , 0) m

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