Consider the fusion reaction 21H+21H?32He+10n. Part A Compute the energy liberat

Question

Consider the fusion reaction 21H+21H?32He+10n.

Part A

Compute the energy liberated in this reaction in MeV and in joules.

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Part B

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Part C

Compute the energy per mole of deuterium, remembering that the gas is diatomic.

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Part D

Compare it with the heat of combustion of diatomic molecular hydrogen, which is about 2.90

Consider the fusion reaction 21H+21H?32He+10n.

Part A

Compute the energy liberated in this reaction in MeV and in joules.

Q = MeV

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Part B

Q = J

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Part C

Compute the energy per mole of deuterium, remembering that the gas is diatomic.

Qfusion = J

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Part D

Compare it with the heat of combustion of diatomic molecular hydrogen, which is about 2.90

Explanation / Answer

2(2.01410178)- ((1* 1.0086654 )+(3.016029)) = 0.00350916 amu released

in Mev , 0.00350916*931.5 = 3.26878254 Mev = 3.26878254 *10^6 *1.6&10^-19

= 5.230052064 *10^-13 J/molecule

for a mole,

5.230052064 *10^-13 J/molecule * 6.023*10^23 = 31.500603581472 *10^10 J/mol

so, for 1 mole of deuterium, 31.500603581472 *10^10 J/mol energy is released.

it is 10.8622770970344828 *10^5 times than heat of combustion of diatomic molecular hydrogen

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