In the figure below, a ball is shot directly upward from the ground with an init

Question

In the figure below, a ball is shot directly upward from the ground with an initial speed of v0 = 8.20 m/s. Simultaneously, a construction elevator cab begins to move upward from the ground with a constant speed vc = 3.90 m/s.

(a) What maximum height does the ball reach relative to the ground?
m

(b) What maximum height does the ball reach relative to the floor of the elevator cab?
m

(c) At what rate does the speed of the ball change relative to the ground? (Include the sign of the value in your answer.)
m/s2

(d) At what rate does the speed of the ball change relative to the cab floor? (Include the sign of the value in your answer.)
m/s2

Explanation / Answer

a) max height when v = 0

v^2 = v0^2 + 2 a y

0 = 8.2^2 - 2*9.81*h

h=3.43 m

b)

so relative to cab vrelative = 8.2-3.9 = 4.3

0 = 4.3^2 - 2*9.81*h

h=0.94 m

c) -9.81 m/s^2

d) -9.81 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects