A diver running 2.7 m / s dives out horizontally from the edge of a vertical cli

Question

A diver running 2.7m/s dives out horizontally from the edge of a vertical cliff and 2.6s later reaches the water below. A.) how high was the cliff? B.) how far from the base did the diver hit? A diver running 2.7m/s dives out horizontally from the edge of a vertical cliff and 2.6s later reaches the water below. A.) how high was the cliff? B.) how far from the base did the diver hit? A diver running 2.7m/s dives out horizontally from the edge of a vertical cliff and 2.6s later reaches the water below. A diver running 2.7m/s dives out horizontally from the edge of a vertical cliff and 2.6s later reaches the water below. A diver running 2.7m/s dives out horizontally from the edge of a vertical cliff and 2.6s later reaches the water below. A.) how high was the cliff? B.) how far from the base did the diver hit? A.) how high was the cliff? B.) how far from the base did the diver hit?

Explanation / Answer

u = 2.7 i m/s

t= 2.6s

so s= 0.5gt2= 33.124 m

so height of the cliff = 33.124 m

now horizpntal distance = u*t= 2.7*2.6=7.02 m

so the diver hit at 7.02 m from the base

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