There are two identical, positively charged conducting spheres fixed in space. T

Question

There are two identical, positively charged conducting spheres fixed in space. The spheres are 48.6 cm apart (center to center) and repel each other with an electrostatic force of F1 = 0.0630 N. Then, a thin conducting wire connects the spheres, redistributing the charge on each sphere. When the wire is removed the spheres still repel but with a force of F2 = 0.115 N. Using this information, find the initial charge on each sphere, q1 and q2 if initially q1 is less than q2.

Please show steps. I want to actually understand this stuff, thanks!

Explanation / Answer

intiall q1 q2

q1 *q2 = 0.063 *0.236/K

Q^2 = 0.115*0.236/K
k=9*10^9
Q =final charge on both equal = 1.732*10^-6 Columbs

let x be amount of charge moved

x = 1.16 *10^-6 C

q1 = Q-x = 0.572*10^-6 C

q2 = 2.892*10^ -6 C

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