Imagine that the standard kilogram is placed on the equator of a planet, where i
ID: 1284091 • Letter: I
Question
Imagine that the standard kilogram is placed on the equator of a planet, where it moves on a circle of radius 7.47 x 106 m (the planet's radius) at a constant speed of 530 m/s due to the planet's rotation. (a) What is the magnitude of the centripetal force on the standard kilogram during the rotation? Imagine that the standard kilogram hangs from a spring balance at that location and assume that it would weigh exactly 7.02 N if the planet did not rotate. (b) What is the reading on the spring balance; that is, what is the magnitude of the force on the spring balance from the standard kilogram?
Explanation / Answer
a) F = m v^2/r = 1*530^2/7.47E6=0.0376 N
b)
mg - T = mv^2/r
T = mg - mv^2/r = 7.02 - 0.0376= 6.98 N