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ID: 1285623 • Letter: C
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CR.E.M.-Losing My x M Eminem: Love Ga x Uust found this on Fa C Home Chegg.com x e 3745 unread) -joey. x C question Chegg.cor x ON-CAPA Three Str 50609534 Q o D 37c305b7 be4b4 559e801 C08a50859f93995ff a97cca C https: e6f554fffa 7ce09 HW #7 (10/23 Th 59 PM Three strings Timer Evaluate Feedback Print Course Contents Notes Three strings, attached the of a rectangular frame, are tied together by a knot as shown in the figure. The magnitude of the tension in the string labeled C is 77.9 N. Calculate the magnitude of the tension in the string marked A 11 iG 1 2 3 4 6 7 8 9 10 11, 12 13 14 x-position (cm) 17.298 N You'll need to get the various positions from the graph. The ends of the strings are exactly on one of the tic marks.) Submit Answer Incorrect. Tries 1/12 Previous Tries Threaded View Chronological View Other Views u Export My general preferences on what is marked as NEW Mark NEW posts no Tonger new NEW Finding FB Matthew Joseph Sopata Reply (Sun Oct 19 01:12:51 pm 2014 (EDT I found all the angles and lengths of each of the strings, and set up the x and y eguations, with the FC known as an integer. I then set the two eguations' FA numbers egual to each other and canceled them out. However, when I solve for FB, it keeps saying that the answer is wrong. Any tips? NEW Re: Finding FB Matthew Joseph Sopata Reply (Sun Oct 19 01:18:24 pm 2014 (EDT Nevermind, figured it out. Accidentally switched the sin and cos for the FB parts of the equations. NEW Re: Re: Finding FB Samuel Joseph Greenwald Reply (Tue Oct 21 12:44:35 pm 2014 (EDT)) How do you do this without knowing A?? NEW Stuck Shelby Ilene Hooper Reply (Tue Oct 21 12:47:30 pm 2014 (EDT)) 4:24 PM 0/22/2014Explanation / Answer
Let the tension in string A be x and that in string B be y
Balancing horizontal tensions,
-x*8/sqrt(8^2+5^2)-y*4/sqrt(4^2+5^2)+77.9*6/sqrt(6^2+3^2)=0
Balancing vertical components,
-x*5/sqrt(8^2+5^2)+y*5/sqrt(4^2+5^2)-77.9*3/sqrt(6^2+3^2)=0
x=32.9N
y=66.9N
Tension in A is 32.9N